This model can be used to determine the null conditions of a Wheatstone bridge or to determine the out-of-null output voltage as a function of arm resistance. Resistors R1 ... R4 are the four arms of the bridge and RL represents the input resistance of the detector or null voltage read-out device. This model requires an iterative solution; the "guess" variable can be the voltage or current in any one of the arms. In the example variable sheet shown below, an off-null sensitivity of 24.8 mV per ohm is demonstrated for a nearly balanced 100 ohm bridge with an excitation voltage of 10 volts and RL=100K.
Variable Sheet _________________________________________________________________________________ St Input Name Output Unit Comment E1 4.9751369 volts Voltage across R1 (volts, mV, µV) I1 .04975137 Amps Current through R1 (Amps, mA, µA) 100 R1 Ohms Resistance of arm 1 (Ohms, Kohms, MOhms) E2 4.9999876 volts Voltage across R2 (volts, mV, µV) I2 .04999988 Amps Current through R2 (Amps, mA, µA) 100 R2 Ohms Resistance of arm 2 (Ohms, Kohms, MOhms) E3 5.0248631 volts Voltage across R3 (volts, mV, µV) I3 .04975112 Amps Current through R3 (Amps, mA, µA) 101 R3 Ohms Resistance of arm 3 (Ohms, Kohms, MOhms) E4 5.0000124 volts Voltage across R4 (volts, mV, µV) I4 .05000012 Amps Current through R4 (Amps, mA, µA) 100 R4 Ohms Resistance of arm 4 (Ohms, Kohms, MOhms) EL 24.85071 mV Voltage across RL (volts, mV, µV) IL 2.4851E-7 Amps Current through RL (Amps, mA, µA) 100000 RL Ohms Resistance of detector (Ohms, Kohms, MOh 10 Vb volts Excitation voltage (volts, mV, µV) Rule Sheet _________________________________________________________________________________ S Rule * E1=I1*R1 "Ohms Law for R1 * E2=I2*R2 "Ohms Law for R2 * E3=I3*R3 "Ohms Law for R3 * E4=I4*R4 "Ohms Law for R4 * EL=IL*RL "Ohms Law for RL * E1+E3=Vb "Kirchoffs Law for voltage * E2+E4=Vb "Kirchoffs Law for voltage * I1=I3+IL "Kirchoffs Law for current * I2=I4-IL "Kirchoffs Law for current * EL=E3-E4 "Kirchoffs Law for voltage